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Hardwood Lumber Grading - the very basics
1) Calculate Board Feet (BF). Measure lumber width, thickness and length. One BF is a piece of lumber that is 1” thick 12” wide and 1 foot long or its equivalent. The formula to figure board feet is as follows:
Thickness * Width * Length
---------------------------- = BF
12
It’s best to round your measurements for simplicity sake. For example you find a piece of Oak lumber that measures 2 1/8” thick, 7 3/4“ wide and 8’ 3” long. Round down the thickness to the nearest 1/4”, width to nearest whole inch and length to the nearest whole foot. In our example we’ll make this piece of oak lumber a thickness of 2 inches, a width of 7 inches and a length of 8 foot, by rounding all three measurements down as specified above.
Thickness (2) * Width (7) * Length (8 )
--------------------------------------- = 9.3 BF
12
2) Calculate Surface Measure (SM). SM is nothing more than the surface measurement of one of the two faces of a piece of lumber. It’s calculated by measuring the width and length of the lumber and dividing the resultant by 12. If the SM calculated winds up to be a fraction, round the fraction to the nearest whole number, (.5 and above up, .49 and below down). Take note that thickness is not taken into account when determining SM.
Width * Length
--------------- = SM (rounded)
12
Again it’s best to round down width to nearest whole inch and length to the nearest whole foot. For our example piece of oak lumber, it measures an actual of 7 3/4” wide and 8’ 3” long. Again for calculation simplicity, we’ll round the width down to 7” and length to 8’
Width (7) * Length (8 )
----------------------- = 4.67 SM (round up) = 5 SM
12
3) Calculate Cutting Units (CU). A Cutting Unit is one inch by one foot or its equivalent. Again note, lumber thickness does not play a role in calculating CU. The formula for CU is merely the multiplication of the width and the length of a piece of lumber. The result is the number of cutting units contained within that piece of lumber. As we’ll see later SM and CU are vital in determining the grade of the piece of lumber.
Width * Length = CU
Similar to SM and for simplicity sake, it’s best to round down the lumber width to it’s nearest whole inch and it’s length to the nearest whole foot. So we’ll multiply 7 x 8 and arrive at 56 cutting units.
Width (7) * Length (8 ) = 56 CU
First a word about defect, for the purpose of my understanding the very basics of hardwood lumber grading, we’ll consider any knot, check, split, dote, hole, wane, worm holes, etc… a defect. What we are after is clear cuttings out of a piece of lumber. The grade rules cover defect and what’s allowed and what’s not per grade and species. Remember when reading this, that it’s my intent to cover grading rules details. Details regarding hardwood grading rules can be found in the latest release of the National Hardwood Lumber Association Hardwood Grade Book. http://www.natlhardwood.org/pdf/2007_Rules.pdf
4) Understand the basics of FAS grade requirements.
* FAS minimum board size is 6” wide by 8’ long. Any board irregardless of how clear it’s faces may be can not meet a FAS grade unless it meets or exceeds the minimum board size.
* A FAS clear cutting can be no smaller than 4 inches wide by 5 foot long or 3” wide and 7’ long. A cutting can be larger, but must be at least be these sizes.
* FAS number of allowable cuts is SM divided by four with a maximum of 4 cuts. The result is rounded down to the nearest whole number (drop any fractions)
SM
---- = FAS allowable cuts (Max 4)
4
* FAS CU Yield is SM times ten. This is the minimum allowable clear wood form the piece of lumber. For a board to make FAS ten twelve’s of it’s wood must be clear and be contained within the minimum FAS Clear cutting size and be cut in the FAS number of allowable cuts
5) example. The example below represents a piece of lumber that is 1 1/8” thick at it’s thinnest section. The black areas represent it’s poorest defective face and the dashed line is where the board would be cut to yield it’s greatest number of clear cutting units. Does it qualify for a FAS grade?
In this example with one allowable cut the board has made the FAS Grade – this is assuming both sides of the board are clear and contained in the clear cutting units made by the single allowable cut. Also note if both edges were clear and there was defect within one foot of the end of the example board, it would also make FAS grade with a width of 10 and a length of 7 resulting in 70 clear cutting units and matching the minimum FAS CU required.
1) Calculate Board Feet (BF). Measure lumber width, thickness and length. One BF is a piece of lumber that is 1” thick 12” wide and 1 foot long or its equivalent. The formula to figure board feet is as follows:
Thickness * Width * Length
---------------------------- = BF
12
It’s best to round your measurements for simplicity sake. For example you find a piece of Oak lumber that measures 2 1/8” thick, 7 3/4“ wide and 8’ 3” long. Round down the thickness to the nearest 1/4”, width to nearest whole inch and length to the nearest whole foot. In our example we’ll make this piece of oak lumber a thickness of 2 inches, a width of 7 inches and a length of 8 foot, by rounding all three measurements down as specified above.
Thickness (2) * Width (7) * Length (8 )
--------------------------------------- = 9.3 BF
12
2) Calculate Surface Measure (SM). SM is nothing more than the surface measurement of one of the two faces of a piece of lumber. It’s calculated by measuring the width and length of the lumber and dividing the resultant by 12. If the SM calculated winds up to be a fraction, round the fraction to the nearest whole number, (.5 and above up, .49 and below down). Take note that thickness is not taken into account when determining SM.
Width * Length
--------------- = SM (rounded)
12
Again it’s best to round down width to nearest whole inch and length to the nearest whole foot. For our example piece of oak lumber, it measures an actual of 7 3/4” wide and 8’ 3” long. Again for calculation simplicity, we’ll round the width down to 7” and length to 8’
Width (7) * Length (8 )
----------------------- = 4.67 SM (round up) = 5 SM
12
3) Calculate Cutting Units (CU). A Cutting Unit is one inch by one foot or its equivalent. Again note, lumber thickness does not play a role in calculating CU. The formula for CU is merely the multiplication of the width and the length of a piece of lumber. The result is the number of cutting units contained within that piece of lumber. As we’ll see later SM and CU are vital in determining the grade of the piece of lumber.
Width * Length = CU
Similar to SM and for simplicity sake, it’s best to round down the lumber width to it’s nearest whole inch and it’s length to the nearest whole foot. So we’ll multiply 7 x 8 and arrive at 56 cutting units.
Width (7) * Length (8 ) = 56 CU
First a word about defect, for the purpose of my understanding the very basics of hardwood lumber grading, we’ll consider any knot, check, split, dote, hole, wane, worm holes, etc… a defect. What we are after is clear cuttings out of a piece of lumber. The grade rules cover defect and what’s allowed and what’s not per grade and species. Remember when reading this, that it’s my intent to cover grading rules details. Details regarding hardwood grading rules can be found in the latest release of the National Hardwood Lumber Association Hardwood Grade Book. http://www.natlhardwood.org/pdf/2007_Rules.pdf
4) Understand the basics of FAS grade requirements.
* FAS minimum board size is 6” wide by 8’ long. Any board irregardless of how clear it’s faces may be can not meet a FAS grade unless it meets or exceeds the minimum board size.
* A FAS clear cutting can be no smaller than 4 inches wide by 5 foot long or 3” wide and 7’ long. A cutting can be larger, but must be at least be these sizes.
* FAS number of allowable cuts is SM divided by four with a maximum of 4 cuts. The result is rounded down to the nearest whole number (drop any fractions)
SM
---- = FAS allowable cuts (Max 4)
4
* FAS CU Yield is SM times ten. This is the minimum allowable clear wood form the piece of lumber. For a board to make FAS ten twelve’s of it’s wood must be clear and be contained within the minimum FAS Clear cutting size and be cut in the FAS number of allowable cuts
5) example. The example below represents a piece of lumber that is 1 1/8” thick at it’s thinnest section. The black areas represent it’s poorest defective face and the dashed line is where the board would be cut to yield it’s greatest number of clear cutting units. Does it qualify for a FAS grade?
5-1) flip board to it’s poorest side, All hardwood is graded according to it’s most defect ridden face. Except for F1F and Select grades which I'll cover later, if I don't fall asleep first.
5-2) First calculate Board Foot (BF)
Thickness 1 * Width 10 * Length 8
---------------------------------- = 6.67 BF
12
5-3) Calculate the surface measure (SM)
Width 10 * Length 8
--------------------- = 6.67 SM (7 rounded)
12
5-4) Calculate the number of cutting units contained in the example
Width 10 * Length 8 = 80 CU
5-5) Calculate number of allowable FAS cutting to make grade
SM (7)
----- = 1.75 FAS allowable cuts (1 fraction dropped)
4
5-6) Calculate FAS CU Yield required
SM (7) * 10 = 70 FAS cutting units required
5-7) calculate CU of clear cutting, Width 9 * Length 8 = 72 Clear Cutting units
5-2) First calculate Board Foot (BF)
Thickness 1 * Width 10 * Length 8
---------------------------------- = 6.67 BF
12
5-3) Calculate the surface measure (SM)
Width 10 * Length 8
--------------------- = 6.67 SM (7 rounded)
12
5-4) Calculate the number of cutting units contained in the example
Width 10 * Length 8 = 80 CU
5-5) Calculate number of allowable FAS cutting to make grade
SM (7)
----- = 1.75 FAS allowable cuts (1 fraction dropped)
4
5-6) Calculate FAS CU Yield required
SM (7) * 10 = 70 FAS cutting units required
5-7) calculate CU of clear cutting, Width 9 * Length 8 = 72 Clear Cutting units
In this example with one allowable cut the board has made the FAS Grade – this is assuming both sides of the board are clear and contained in the clear cutting units made by the single allowable cut. Also note if both edges were clear and there was defect within one foot of the end of the example board, it would also make FAS grade with a width of 10 and a length of 7 resulting in 70 clear cutting units and matching the minimum FAS CU required.