You also have the advantage at 220V of having a less of a percentage of voltage droop.
For example if the resistance of circuit was 1 ohm (not out of question).
If full load current draw at 120V was 20 amps than voltage drop would be (20*1)= 20V which means the motor would have 100V at its input which means its running at 83% (100/120) of rated voltage.
At 220V the current would be 10Amps and the voltage drop would be 10*1 = 10V and which translates to 210V at its input and translates to 95% (210/220) of rated voltage.
Motors will definitely run noticeably better (and cooler) at 95% than 83% of rated voltage.
For example if the resistance of circuit was 1 ohm (not out of question).
If full load current draw at 120V was 20 amps than voltage drop would be (20*1)= 20V which means the motor would have 100V at its input which means its running at 83% (100/120) of rated voltage.
At 220V the current would be 10Amps and the voltage drop would be 10*1 = 10V and which translates to 210V at its input and translates to 95% (210/220) of rated voltage.
Motors will definitely run noticeably better (and cooler) at 95% than 83% of rated voltage.